Removing the first part of a concatenated string with Python

Question

I have a string as follows

CompilationStatistics_Compilation_StepList_Map_TimingUsage_ClockList_Clock_MinimumPeriod

What would be the simplest way to remove the first part (CompilationStatistics_) or the last part (_MiniumuPeriod)?

I think about using regular expression, but I expect there should a better way.

m = re.search("{.+}_{.+}", string)
m.group(2)

Answer 1

If you know the size of the chunks you want to cut out, you can use Python's string slicing, like this:

s="CompilationStatistics_Compilation_StepList_Map_TimingUsage_ClockList_Clock_MinimumPeriod"
print s[22:-14]

Of course, there are other ways you can find the number you need, like using String.rindex() to find the place where the end chunk you want to cut off starts. For example:

print s[len("CompilationStatistics_"):s.rindex("_MinimumPeriod")]

Answer 2

All but first:

s[s.find('_') + 1:]

All but last:

s[0:s.rfind('_')]

Without either:

s[s.find('_') + 1:s.rfind('_')]

find returns the first index of the string, and rfind returns the last. Then, we just use slice syntax.

Answer 3

See the Python documentation for String methods, particularly partition and rpartition:

s = "CompilationStatistics_Compilation_StepList_Map_TimingUsage_ClockList_Clock_MinimumPeriod"
print s.partition('_')[2].rpartition('_')[0]

Result

Compilation_StepList_Map_TimingUsage_ClockList_Clock

Answer 4

'_'.join(s.split("_")[1:-1])?

Changing the splice numbers will change how much you get: removing the "-1" will only remove the first item, for example.

Answer 5

Removing the first part is trivially down with split():

s.split("_", 1)[1] # Take the second part of the string, split into 2 pieces.