Android Button Position Programmactically

Question

Hello,

I have a button in my application.... I want to change its position by programmatically...

I have created a button in xml as follows:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    >


<Button android:text="@+id/Button01" 
        android:id="@+id/Button01" 
        android:layout_width="wrap_content" 
        android:layout_height="wrap_content"
        android:layout_marginLeft="50px"
        android:layout_marginTop="10px"
        >
</Button>
</LinearLayout>

suppose if i wants to set the position of button as 100px from Left (as layout_marginLeft="100px") then how do i do it programatically?

pls help me and take me out from this problem. Thanx - Paresh

Answer 1

You need to get the view and transform into a Java object, then call setPadding on it.

some thing like this would work out

Button myBtn;
myBtn=(Button)findViewById(R.id.Button01);
myBtn.setPadding(0,100,0,0);

Read more here: http://developer.android.com/intl/de/reference/android/view/ViewGroup.MarginLayoutParams.html

Answer 2

Padding and margin are not the same ... this is thread is what you are looking for http://stackoverflow.com/questions/2481455/set-margins-in-a-linearlayout-programmatically