Does python have a non-lazy version of itertools.groupby?

Question

I don't need the laziness of itertools.groupby. I just want to group my list into a dict of lists as such:

dict([(a, list(b)) for a,b in itertools.groupby(mylist, mykeyfunc)])

Is there a standard function that already does this?

Answer 1

It sounds like you have a one-line function already that does what you want. Use it.

Answer 2

No, there's not a function included in the standard library to do this.