String.split(String regex)
takes a regular-expression pattern. It just so happens that .
in regex is a metacharacter that matches (almost) any character, hence why split(".")
doesn't work the way you expected.
You can escape the .
by preceding it with a backslash. As a Java string literal, this is "\\."
. The \
is doubled because \
itself is a Java escape character. "\\."
is a String
of length 2, containing a backslash and a period.
If you're given an arbitrary String
that is to be matched literally (or if you just don't care to escape them yourself), you can use Pattern.quote
. It'll make a pattern to literally match a given String
.
See also
This is provided for educational purposes only:
String text =
"Wait a minute... what?!? Oh yeah! This is awesome!!";
for (String part : text.split("(?<=[.?!]) ")) {
System.out.println(part);
}
This prints:
Wait a minute...
what?!?
Oh yeah!
This is awesome!!
References
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