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Answer 1

+2 A:

You're using a regular hyperlink, no form will get posted. you need a submit button of some kind in a form with method="post" to do that. regular links just result in GET requests and nothing will ever be posted that way.

edit: added simple example:

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN">
<html>
    <head>
        <title>Form test</title>
    </head>
    <body>
<?if ($_SERVER['REQUEST_METHOD'] == 'POST'):?>
        <pre><? print_r($_POST)?></pre>
<?endif;?>
        <? // $_SERVER['REQUEST_URI'] holds the current URL, so we know that ?>
        <? // we'll end up back in this file when the form is submitted.     ?>
        <form method="post" action="<?= $_SERVER['REQUEST_URI']; ?>">
            <input type="text" name="textbox" 
                value="<?= isset($_POST['textbox'])?$_POST['textbox']:'Type something' ?>" />
            <input type="submit" name="submitbutton" value="Submit" />
        </form>
    </body>
</html>

Kris 2010-07-17 20:55:24

Answer 2

+3 A:

a isnt a form control. it needs to be an input or select if it's within a form.

For manual linking, do href="/page?logout"

meder 2010-07-17 20:55:37

Answer 3

+1 A:

$_POST will only be filled if you use a form with method=post.

Femaref 2010-07-17 20:56:00

Answer 4

A:

Yes. A POST and a GET are two different things ;)

if(isset($_GET['logout']))

hollsk 2010-07-17 20:56:24

Answer 5

+3 A:

If you click the link, nothing happens because the URL only contains the fragment identifier #. Not even a GET request will be issued.

You use this kind of link normally to jump to an element inside the page (e.g. <a href="#top">Top</a> to jump to an element with ID top). This is completely handled in the browser.

And if you only put the fragment identifier there, just nothing will happen. This is very often used if the link should execute some JavaScript and should actually not link to something else.

You are testing the $_POST array at the server side. But this array only contains elements, if you initiate a POST request by a form. That means you need to create a form with a submit button, e.g.:

<form action="" method="POST">
    <input type="submit" name="logout" value="Exit Group" />
</form>

Here comes the name attribute into play, which will be the key in the $_POST array. But assigning this on a normal link will have no effect.

You could do it also with the link, but with a GET request this way:

<a id="exit" href="?logout=1">Exit Group</a>
<!--                 ^-- parameter must be part of the URL, name has no effect    -->

and

if(isset($_GET['logout'])){    
    //CODE TO BE EXECUTED        
}

Note that you have to pass a parameter logout it here.

It seems you have mixed up GET and POST requests. If you have a form, the name s of the form elements will be transmitted as parameters to the server. That means given this form:

<form method="POST">
    <input type="text" name="foo" value="" />
    <input type="text" name="bar" value="" />
    <input type="submit" name="send" value="Send" />
</form>

if the user clicks on the submit button, the $_POST array at the server side will have the keys:

$_POST['foo']
$_POST['bar']
$_POST['send']

This does not work with links though. A click on a link will create a normal GET request, and here, the parameters must be part of the URL, appended after a question mark ? and separated by an ampersand &:

<a href="somePage.php?foo=1&bar=1&andMore=0"> Link </a>

will result in

$_GET['foo']
$_GET['bar']
$_GET['andMore']

You probably should read about the HTTP protocol.

Felix Kling 2010-07-17 20:57:58

SORRY everyone, but I should have mentioned that IT DOES NOT WORK with $_GET either. I tried it before, thus thought $_POST would work, but BOTH OF THEM don't work.

Newbie_25 2010-07-17 21:00:57

@newbie-25: Read the first paragraph of my answer. The URL you use is wrong.

Felix Kling 2010-07-17 21:03:28

Are you actually passing any URL parameters? Your example doesn't have any, is it a faithful representation of what you're doing?

hollsk 2010-07-17 21:04:44

Answer 6

A:

This <a id="exit" name="logout" href="#"> should be <a id="exit" href="?logoff=true#">.

Then logoff will be in the $_GET array.

Michael Speer 2010-07-17 21:09:24

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