append tuples to a list

Question

How can I append the content of each of the following tuples (ie, elements within the list) to another list which already has 'something' in it? So, I want to append the following to a list (eg: result[]) which isn't empty:

l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]

Obviously, the following doesn't do the thing:

for item in l:
    result.append(item)
    print result

I want to printout:

[something, 'AAAA', 1.11] 
[something, 'BBB', 2.22] 
[something, 'CCCC', 3.33]

Please help. Many thanks in advance.

Answer 1

result.extend(item)

Answer 2

You can use the inbuilt list() function to convert a tuple to a list. So an easier version is:

l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]
result = [list(t) for t in l]
print result

Output:

[['AAAA', 1.1100000000000001],
 ['BBB', 2.2200000000000002],
 ['CCCC', 3.3300000000000001]]

Answer 3

You will need to unpack the tuple to append its individual elements. Like this:

l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]

for each_tuple in l:
  result = ['something']
  for each_item in each_tuple:
    result.append(each_item)
    print result

You will get this:

['something', 'AAAA', 1.1100000000000001]
['something', 'BBB', 2.2200000000000002]
['something', 'CCCC', 3.3300000000000001]

You will need to do some processing on the numerical values so that they display correctly, but that would be another question.

Answer 4

You can convert a tuple to a list easily:

>>> t = ('AAA', 1.11)
>>> list(t)
['AAAA', 1.11]

And then you can concatenate lists with extend:

>>> t = ('AAA', 1.11)
>>> result = ['something']
>>> result.extend(list(t))
['something', 'AAA', 1.11])