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i found on web function to encode string to 64

Function Base64Encode(inData)
'rfc1521
'2001 Antonin Foller, Motobit Software, http://Motobit.cz

Const Base64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
Dim cOut, sOut, I

'For each group of 3 bytes

For I = 1 To Len(inData) Step 3
Dim nGroup, pOut, sGroup

'Create one long from this 3 bytes.

nGroup = &H10000 * Asc(Mid(inData, I, 1)) + _
&H100 * MyASC(Mid(inData, I + 1, 1)) + MyASC(Mid(inData, I + 2, 1))

'Oct splits the long To 8 groups with 3 bits

nGroup = Oct(nGroup)

'Add leading zeros

nGroup = String(8 - Len(nGroup), "0") & nGroup

'Convert To base64

pOut = Mid(Base64, CLng("&o" & Mid(nGroup, 1, 2)) + 1, 1) + _
Mid(Base64, CLng("&o" & Mid(nGroup, 3, 2)) + 1, 1) + _
Mid(Base64, CLng("&o" & Mid(nGroup, 5, 2)) + 1, 1) + _
Mid(Base64, CLng("&o" & Mid(nGroup, 7, 2)) + 1, 1)

'Add the part To OutPut string

sOut = sOut + pOut

'Add a new line For Each 76 chars In dest (76*3/4 = 57)
'If (I + 2) Mod 57 = 0 Then sOut = sOut + vbCrLf

Next
Select Case Len(inData) Mod 3
Case 1: '8 bit final

sOut = Left(sOut, Len(sOut) - 2) + "=="
Case 2: '16 bit final

sOut = Left(sOut, Len(sOut) - 1) + "="
End Select
Base64Encode = sOut
End Function

Function MyASC(OneChar)
 If OneChar = "" Then MyASC = 0 Else MyASC = Asc(OneChar)
 End Function

but my string is in hebrew and it's dosen't work.

any idea?