Hi,
My text:
var str = 'Cost USD 400.00';
How do i use jquery to find number only in that str?
+3
A:
You probably shouldn't use JQuery for that; you should use built-in Javascript regular expression support. In this case your regular expression might look like:
var result = /\d+(?:\.\d+)?/.exec(mystring);
The official reference for this is at https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Objects/RegExp .
Reinderien
2010-07-22 17:03:20
you may wish to follow that with parseFloat() to turn into a number
second
2010-07-22 17:06:11
Your solution doesn't work: http://jsfiddle.net/3LmHH/
patrick dw
2010-07-22 17:21:30
Change "\\" to "\". But it is returning any number, not an integer. Is it really what the OP want?
BrunoLM
2010-07-22 17:24:35
A:
Just search for the number using a plain RegEx object in javascript. No need for jquery here.
e.g :
var str = new RegExp("\\d+(?:\\.\\d+)");
var num = str.exec("Cost USD 400.00");
gillyb
2010-07-22 17:06:56
The 'test' method would return true if there is a number, but wouldn't actually give you the number back. In addition, you wouldn't get the ".00" from this regex.
Reinderien
2010-07-22 17:10:12
I immidiatly realized i posted the start method instead of .exec, so i changed it. About the regular expression, I meant to add on to your (@Reinderien) answer, and just wanted to give damien the code he could actually use, because it seems like he doesn't know how to, and that was before you edited your answer.
gillyb
2010-07-22 17:14:55
A:
What gillyb said but I'd just add:
var str=new RegExp("\\d+\.?\d+?");
To pick up anything after the decimal point.
The above RegEx should match
400
400.01
400.0
400.001
I often use http://xenon.stanford.edu/~xusch/regexp/analyzer.html when building regular expressions... but you also might find this one very useful http://www.regular-expressions.info/javascriptexample.html
if you put the regex on line one, the string your testing against on line 2 then you can see what gets put into the variable with the SHOW MATCH button.
Try it with variations of the above numbers and see what comes back.
Alex C
2010-07-22 17:19:52