Hey guys can you help me with this. I've got this '/[^A-Za-z]/' but cannot figure out the punctuations part.
Gracious!
+1
A:
/[^A-Za-z]*/ will match everything except letters. You shouldn't need to specify numbers or punctuation.
kurreltheraven
2010-07-23 02:26:14
While what you said is true, it doesn't answer the question. See kiamlaluno's answer.
Jamie Wong
2010-07-23 02:29:05
Actually for what I'm doing kurrel is right. but this is a mistake in how I asked the question and in my own code execution. - 2 for me, my apologies. My original regex actually works as needed.
atwellpub
2010-07-23 02:45:29
kiamlaluno's second version is more flexible with respect to extra characters for sure, but if you're using the regex in say an if-statement to match what you don't want, you're going to be looking for negatives instead of positives.
kurreltheraven
2010-07-23 03:09:34
+3
A:
The regular expression you are using doesn't allow letters; it's the opposite of what you are reported in the title.
/[a-z]/i is enough, if you want to accept only letters. If you want to allow letters like à, è, or ç, then you should expand the regular expression; /[\p{L}]/ui should work with all the Unicode letters.
kiamlaluno
2010-07-23 02:26:58
A:
#^[^a-z]+$#i
Your code was correct, you just need ^ and $. So it means all character from the beginning to the end doesn't allow outside alphabet. Negative match is preferred than positive match here.
iroel
2010-07-23 03:34:54
it means like this: <code>if (preg_match('#^[^a-z]+$#i', $string) echo 'outside alphabet found';</code>
iroel
2010-07-23 05:47:24