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58

answers:

3

I assume that you can include "?" in your sqlite statement, provided in the "executeQuery" method, you pass additional arguments corresponding to each "?". But when I put this to practice, the results are not consistent.

This statement works:

SELECT * FROM answers WHERE test_id = ? and question_id = ?

with this method

FMResultSet * answer = [[UIApp database] executeQuery:[Queries getTheAnswer], l, n];

The following statement crashes the program when I include a "?"

SELECT * FROM questions where test_id = ? ORDER BY RANDOM() LIMIT ?
FMResultSet * set = [[UIApp database] executeQuery:[Queries randomNumberOfVerses], selectedTests, numRounds];

But works fine when I hardcode a value in.

SELECT * FROM questions where test_id = 5 ORDER BY RANDOM() LIMIT ?
FMResultSet * set = [[UIApp database] executeQuery:[Queries randomNumberOfVerses], numRounds];

Any suggestions since I don't want to hardcode values in? All variable used as arguments are of type NSNumber*

+1  A: 

I don't know the iPhone or Objective C, but usually ? arguments are used for prepared statements, rather than "immediate mode" queries.

In the SQLite C API, the functions you're interested in are called sqlite3_prepare*().

If you can figure out what the Objective C mapping is for those, you should be able make some progress.

Edit:

I almost forgot the part that actually answers your question...

Once you have a prepared statement, use the sqlite3_bind*() functions to give values to the query parameters.

Drew Hall
A: 

Have a look at this article it gives all the code you need.

Jules
A: 

While WHERE clauses can include bind-parameters, the LIMIT argument cannot. It has to be an integer literal. See the SQLite Syntax Diagram.

Given that, I'm not sure why your last one is working. It should be fine if you hardcode the LIMIT argument, leaving the test_id = ?, but it shouldn't work when you use ? for the LIMIT.

Daniel Dickison