Check Sessions in an array ?

Question

hmm i got a homework, its 2 hours and i still have no clue on it :|

like this

$sessions['lefthand'] = 'apple';
$sessions['righthand'] = '';
$sessions['head'] = 'hat';
$sessions['cloth'] = '';
$sessions['pants'] = '';

// here is the homework function
CheckSession('lefthand,righthand,head,cloth,pants');

we have some string "lefthand,righthand,head,cloth,pants" question is : " how can we check if the five session is not null or exist and display which session is empty ( if there is an empty session ) if all exist then returns a true ?

empty righthand , pants, and cloth.

this is how i think about it

1. explode it to arrays
2. check one bye one if !null id there is a

here is the progress that ive made *edit4 , :)

function CheckSession($sessions){
$all_sessions_exist = true;
$keys = explode(',',$sessions);
$error = array();
    // Search for Session that are not exist
    foreach ($keys as $key) {
        if (!isset($_SESSION[$key]) && empty($_SESSION[$key])) {
            echo "no $key</br>";
            $all_sessions_exist = false; 
        }
    }
return $all_sessions_exist;
}

Thanks for taking a look

Adam Ramadhan

Answer 1

Seeing as it's homework, you won't get the solution. You're on the right track though. explode() it by the delimiter. You can the loop through it using foreach and use empty() to check if they're set. You can access the sessions like $_SESSION[$key]. Keep an array of the ones that match.

Answer 2

function CheckSession($string){
    $all_sessions_exist = true; #this will change if one of the session keys does not exist
    $keys = explode(',', $string); #get an array of session keys
    foreach($keys as $key){
        if(isset($_SESSION[$key])) {
            if(!empty($_SESSION[$key])) 
                echo '$_SESSION['.$key.'] is set and contains "'.$_SESSION[$key].'".'; #existing non-empty session key
            else echo '$_SESSION['.$key.'] is set and is empty.' ;
        }else {
             echo '$_SESSION['.$key.'] is not set.'; #key does not exist
             $all_sessions_exist = false; #this will determine if all session exist
        }

        echo '<br />'; #formatting the output
    }

    return $all_sessions_exist; 
}

Answer 3

Just cleaning up your function

function CheckSession($sessions)
{
    $session = explode(',',$sessions);
    $return = array();
    foreach ($session as $s)
    {
        $return[$s] = (isset($_SESSION[$s]) && !empty($_SESSION[$s]) ? true : false)
    }
    return $return;
}

$sessions['lefthand'] = 'apple';
$sessions['righthand'] = '';
$sessions['head'] = 'hat';
$sessions['cloth'] = '';
$sessions['pants'] = '';

And the checking part

// here is the homework function
$Results = CheckSession('lefthand,righthand,head,cloth,pants');

---

Edit

//$value1= false; // Commented out so does not get set
$value2= false; //Still set to a bool

error_reporting(E_ALL);

empty($value1); // returns false but still strikes E_NOTICE ERROR
empty($value2); // returns false with no error

Note, empty does not trigger an error but this example would take affect an a lot of other php functions.