How can I choose which version of a module to include dynamically in Ruby?

Question

I'm writing a small Ruby command-line application that uses fileutils from the standard library for file operations. Depending on how the user invokes the application, I will want to include either FileUtils, FileUtils::DryRun or FileUtils::Verbose.

Since include is private, though, I can't put the logic to choose into the object's initialize method. (That was my first thought, since then I could just pass the information about the user's choice as a parameter to new.) I've come up with two options that seem to work, but I'm not happy with either:

1. Set a global variable in the app's namespace based on the user's choice, and then do a conditional include in the class:

   class Worker
     case App::OPTION
     when "dry-run"
       include FileUtils::DryRun
       etc.
   

2. Create sub-classes, where the only difference is which version of FileUtils they include. Choose the appropriate one, depending on the user's choice.

   class Worker
     include FileUtils
     # shared Worker methods go here
   end
   class Worker::DryRun < Worker
     include FileUtils::DryRun
   end
   class Worker::Verbose < Worker
     include FileUtils::Verbose
   end
   

The first method seems DRY-er, but I'm hoping that there's something more straightforward that I haven't thought of.

Answer 1

So what if it's private?

class Worker
  def initialize(verbose=false)
    if verbose
      (class <<self; include FileUtils::Verbose; end)
    else
      (class <<self; include FileUtils; end)
    end
    touch "test"
  end
end

This includes FileUtils::something in particular's Worker's metaclass - not in the main Worker class. Different workers can use different FileUtils this way.