I have a string like this:
" 23 PM"
I would like to remove 23 so I'm left with PM or (with space truncated) just PM.
Any suggestions?
Needs to be in PHP
views:
71answers:
7
+2
A:
Can do with ltrim
ltrim(' 23 PM', ' 0123456789');
This would remove any number and spaces from the left side of the string. If you need it for both sides, you can use trim. If you need it for just the right side, you can use rtrim.
Gordon
2010-07-29 13:35:59
care to explain the downvote?
Gordon
2010-07-29 13:49:56
@Gordon: same thing happened to my answer too. Looks like it's poor sportsmanship on someone's behalf. +1 from me for offering a valid non-regex solution, anyway.
Andy E
2010-07-29 13:51:48
Even this would match all digits, I guess it would be faster with the asterisk after the paranthesis, like in my answer.
faileN
2010-07-29 13:47:19
It's not going to make much difference in speed using an astrisk vs not... And even at that, you're talking about a time value with 4 zeros after the decimal point anyway (0.00001 seconds or so), so unless you're doing it in a loop (a large loop), there's no point in trying to optimize a statement like this...
ircmaxell
2010-07-29 13:50:48
Space removing wasn't the main point of view. But it's really easy to do that too. Just put space into brackets: [0-9 ]
System
2010-07-29 14:28:06
+2
A:
Can also use str_replace, which is often the faster alternative to RegEx.
str_replace(array(1,2,3,4,5,6,7,8,9,0,' '),'', ' 23 PM');
// or
str_replace(str_split(' 0123456789'), '', ' 23 PM');
which would replace any number 0-9 and the space from the string, regardless of position.
Gordon
2010-07-29 13:41:22
This would say, that the numbers have to be on the left side, and that there must be at least one number. This fits for the example he provided, but in general this solution wouldn't work. What about strings like "AM 23423NNfB"? You couldn't remove the numbers with your regex.
faileN
2010-07-29 13:46:03
It answers the request of the op, he didn't say anything about what there is after PM.
M42
2010-07-29 13:50:41
He said. "I've got a string LIKE...." And the headline of the topic says generally: Remove spaces from string. So I understand "ANY String".
faileN
2010-07-30 07:54:02
Literal is sometimes the best option, without further description from the OP.... and my solution wasn't much different to your own
Mark Baker
2010-07-29 14:16:16
+1
A:
If you just want the last two characters of the string, use substr with a negative start:
$pm = substr(" 23 PM", -2); // -> "PM"
Andy E
2010-07-29 13:45:59
upvoting this to compensate unjustified downvote and also because the OP is not clear about the strings he expects and Andy explicitly stated what the code above does.
Gordon
2010-07-29 13:53:59