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views:

32

answers:

0

Hello guys

this is my code

// build query string
$searchUrl = "http://www.dezrez.com/DRApp/Search.ASP?WCI=Results&GType=" 
           . $_POST["GType"] . "&EAID=" . $_POST["EAID"] 
           . "&perpage=" . $_POST["perpage"] . "&StyleSheet=" 
           . $_POST["StyleSheet"] . "&xslt=" . $_POST["xslt"] 
           . "&priceOrder=" . $_POST["priceOrder"] . "&ShowSTC=" 
           . $_POST["ShowSTC"] . "&MinPrice=" . $_POST["MinPrice"] 
           . "&MaxPrice=" . $_POST["MaxPrice"] . "&bid=" 
           . $_POST["bid"] . "&Bedrooms=" . $_POST["Bedrooms"] 
           . "&rentalperiod=" . $_POST["rentalperiod"] 
           . "&Glazing_type" . $_POST["Glazing_type"];

// Fetch the remote URL and store it to disk
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $searchUrl);
$fp = fopen('searchResult.xml', 'w');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_exec($ch);
curl_close($ch);
fclose($fp);

// read fetched XML from local file
$xmlDoc = new DOMDocument();
$xmlDoc->load('searchResult.xml');
$properties = $xmlDoc->getElementsByTagName("property");
foreach ($properties as $property) {
    $description = $property->getElementsByTagName("description");
}

I want to open above link("searchUrl") internally and then want to read every node of xml file getting from this searchUrl so that i cant put that information in proper format. If you want to know more about this please go to This link, hope you will understand everything what i want to do ..

Note: this is a follow-up to saving and reading a xml file getting from the other url