i will be comparing two values like this:\
value1>value2
i know that value2 is always an integer, but sometimes value1 is None or a string, how do force the comparison ONLY if value1 is numerical?
value1 is a decimal
+2
A:
Python 3
try:
value1 > value2
except TypeError:
pass
Python <3
if isinstance( value2, int ):
value1 > value2
This latter is unpythonic, because this type of comparison is unpythonic. You should filter your data first.
katrielalex
2010-07-30 22:36:40
can you use this on a decimal also?
I__
2010-07-30 22:41:53
Yes. The former because Py3k won't let you compare distinct types, and the latter because we *only* allow `int`s. You should try and think a bit about what the code is doing before asking such simple questions.
katrielalex
2010-07-30 22:49:08
http://stackoverflow.com/questions/3375913/python-is-there-an-iserror-function
I__
2010-07-30 22:50:39
That's completely unrelated.
katrielalex
2010-07-30 22:52:19
The `int` cast won't work pleasantly on a decimal. And the `isdigit()` only works on strings. You can check for the existance of `isdigit` with `hasattr` and change the `int` to `Decimal` to make sure you can compare both ints and Decimals.
WoLpH
2010-07-30 22:48:00
As I said, that only works for strings. However, if your input is sanitized (all the strings can be casted to `Decimal`) than you can do with a simple `if value1` and a `Decimal(value1) > value2`
WoLpH
2010-07-30 23:41:50