Get the size of an image file

Question

Images and script hosted on the same account (one site).

We know direct link to each image:

$image = "http://site.com/images/full-1091.jpg"

How can we get the size of this file?

Like:

{ do something with $image and get $image_size }
echo $image_size;

Its better to format $image_size like "156,8 Kbytes" or "20,1 Mbytes".

Thanks.

Answer 1

 echo filesize($_SERVER['DOCUMENT_ROOT']."/images/full-1091.jpg");

note that http://site.com/images/full-1091.jpg is not a file

as for the formatted output ("156,8 Kbytes" or "20,1 Mbytes") try to help yourself and use search. There is a ton of answers to this question already.

Answer 2

Images and script hosted on the same account (one site).

Then don't use a URL: Use the direct file path and filesize().

Answer 3

Use filesize function like this:

echo filesize($filename) . ' bytes';

You can also format the unit of the size with this function:

function format_size($size) {
      $sizes = array(" Bytes", " KB", " MB", " GB", " TB", " PB", " EB", " ZB", " YB");
      if ($size == 0) { return('n/a'); } else {
      return (round($size/pow(1024, ($i = floor(log($size, 1024)))), 2) . $sizes[$i]); }
}

Answer 4

<?php
  $contents=file_get_contents("http://site.com/images/full-1091.jpg");
   // var_dump($contents);
//  $fp =fopen("1.jpeg","w");
  file_put_contents("1.jpeg",$contents);
  $size= filesize("1.jpeg");
  echo $size."in Bytes";
  ?>

Check this it can work for you