preg_replace remove only part of a string but leave the rest using PHP

Question

I am trying to do a replace within a string in PHP. How do you delete the part that is only in the group in PHP?

<font.+?(size.+?.)>

I want to remove size=x where ever it in. The problem is I cannot get the

 $text = preg_replace("<font.+?(size.+?.)>","",$text);

function to work.

Example source of this

<font style="background-color: rgb(255, 255, 0);" size="2"><strong><u>text</u></strong></font>
<font size="2">more text</font>

into this

<font style="background-color: rgb(255, 255, 0);" ><strong><u>text</u></strong></font>
<font>more text</font>

I am trying to say. Where ever there is a font tag and if I see size-anything remove the size attribute, but leave everything else i tact.

Thanks again...

Answer 1

Regex is a poor way of doing HTML manipulation, but that said, the general technique to do this kind of regex matching and partial replacement is to match:

(<font.+?)(size.+?.)(>)
\________/\________/\_/
    1         2      3

And then replace with

$1$3

This substitutes into the replacement backreferences to what group 1 and group 3 matched, leaving group 2 out, effectively deleting what group 2 matched.

References

• regular-expressions.info/Brackets for Grouping and Backreferences

Answer 2

$dom = new DOMDocument();
$dom->loadHTML($htmlstring);
$x = new DOMXPath($dom);
$list = $x->query('//font/@size');
for($i = $list->length-1;$i>=0;$i--){
    $attr = $list->item($i);
    $attr->ownerElement->removeAttributeNode($attr);
}

Answer 3

Not the best solution, but to answer your question:

$html = <<<END
<font style="background-color: rgb(255, 255, 0);" size="2"><strong><u>text</u></strong></font>
<font size="2">more text</font>
END;

$text = preg_replace('/(<font.*?)(size\s*=[^\s>]*)([^>]*)>/si', '\1\3>', $html);
var_dump($text);