I have a string that contains html markup like links, bold text, etc.
I want to strip all the tags so I just have the raw text.
What's the best way to do this? regex?
I have a string that contains html markup like links, bold text, etc.
I want to strip all the tags so I just have the raw text.
What's the best way to do this? regex?
If you are going to use regex:
import re
def striphtml(data):
p = re.compile(r'<.*?>')
return p.sub('', data)
>>> striphtml('<a href="foo.com" class="bar">I Want This <b>text!</b></a>')
'I Want This text!'
Depending on whether the text will contain '>' or '<' I would either just make a function to remove anything between those, or use a parsing lib
def cleanStrings(self, inStr):
a = inStr.find('<')
b = inStr.find('>')
if a < 0 and b < 0:
return inStr
return cleanString(inStr[a:b-a])
AFAIK using regex is a bad idea for parsing HTML, you would be better off using a HTML/XML parser like beautiful soup.
Use SGMLParser
. regex
works in simple case. But there are a lot of intricacy with HTML you rather not have to deal with.
>>> from sgmllib import SGMLParser
>>>
>>> class TextExtracter(SGMLParser):
... def __init__(self):
... self.text = []
... SGMLParser.__init__(self)
... def handle_data(self, data):
... self.text.append(data)
... def getvalue(self):
... return ''.join(ex.text)
...
>>> ex = TextExtracter()
>>> ex.feed('<html>hello > world</html>')
>>> ex.getvalue()
'hello > world'
Use lxml.html. It's much faster than BeautifulSoup and raw text is a single command.
>>> import lxml.html
>>> page = lxml.html.document_fromstring('<!DOCTYPE html>...</html>')
>>> page.cssselect('body')[0].text_content()
'...'