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Need regex to match two rather similar URL patterns

Answer 1

+1 A:

Use this regex

^/\d{4}/[^/]*?$

Gopi 2010-08-04 06:06:42

The important point here is the start and end anchors, `^` and `$`. Without them, the regex can match `/2010/08/` **`01/text_text`**.

Kobi 2010-08-04 06:19:46

As modified to capture the two pieces I need:`^/(\d{4})/([^/]*?)$`Thank you!

AndrewRich 2010-08-04 06:22:07

Answer 2

+1 A:

Try this:

^/(\d{4})/(\w+)$

fuwaneko 2010-08-04 06:06:42

This worked, thank you!

AndrewRich 2010-08-04 06:25:57

I didn't know \w included numbers, but this definitely seems to work. Nice simple pattern.

Dunderklumpen 2010-08-04 06:28:12

\w includes any "word" character, i.e. digits, letters and underscore. However implementations may vary, and include other characters.

fuwaneko 2010-08-04 06:32:54

Answer 3

A:

If the entire string is only the URL, you could try the following pattern:

^/[0-9]+/(([0-9]{4}_)?[^/]+)$

A quick explanation of my approach

^ represents the beginning of the string, $ the end of the string
/[0-9]+/ is the first number URL
([0-9]{4}_)? is the additional optional starting four digit number.
[^/]+ will represent any characters not including a forward slash to the end of the string.

Dunderklumpen 2010-08-04 06:10:16

I don't think the OP is looking to capture the second number, so `([0-9]{4}_)?` may be redundant.

Kobi 2010-08-04 06:17:45

Actually the parens here are merely to allow the '0 or 1' operator on the four numbers. As a side-effect they could be captured, but can also be ignored.

Dunderklumpen 2010-08-04 06:25:57

This one did not work for me. Matching was as expected but the second part was not captured.

AndrewRich 2010-08-04 06:26:52

I did leave out the second capture. ^/[0-9]+/(([0-9]{4}_)?[^/]+)$ will do it.

Dunderklumpen 2010-08-04 06:31:23

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Need regex to match two rather similar URL patterns

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