Merge variables

Question

We have $id and $title variables, which everytime change.

For each $id we should create a new variable $temp_title_%id%, and give to it $title's value.

Like:

$id = 10;
$title = 'Hello people!';
$temp_title_10 = 'Hello people!';

Tryed this (doesn't work):

$temp_title_ . $id = $title;

Thanks.

Answer 1

I think it's a bad idea to do what you're trying to do, but here's how to do it anyways:

$GLOBALS["temp_title_".$id]=$title;

Alternatively, you could do this:

$varname="temp_title_".$id;
$$varname=$title;

The most correct way to do what I think you're trying to do would be to use an array:

// Somewhere in the PHP script:
$an_array=array();

// To assign:
$an_array[$id]=$title;

// To retrieve:
echo $an_array[$id];

Answer 2

Use this:

$metavariable = "temp_title_".$id;
$$metavariable = $title;  // note the $$

Answer 3

If you're trying to persist your variables, it would probably be better to place them in an array if your $id variable will always be an integer.

$persistence_array = array();

while (some_requirement) {
    $id = ...;
    $title = ...;
    $persistence_array[$id] = $title;
}

If $id might also contain alpha-numeric data, then you could always use a hash / dictionary in the same way (with a small amount of additional logic you could even store multiple values for the same id).

DON'T DO THIS: If you absolutely must have variables then you can use variable variables But please, don't.

Answer 4

How about using an array instead? An array is a much better way of storing multiple values. Much, much, much better.

$title_array = array();

$id = 10;
$title = 'Hello people!';
$title_array[$id] = $title;

Answer 5

${'temp_title_' . $id} = $title;
echo $temp_title_10;

Answer 6

Use variable variable of PHP http://php.net/manual/en/language.variables.variable.php

$variable = $title.'_'.$id
$$variable = 'hello, world!'