views:

185

answers:

2

Hi there,

I am a total beginner to programming and Django so I'd appreciate help that beginner can get his head round!

I was following a tutorial to show how to upload images to an Amazon S3 account with the Boto library but I think it is for an older version of Django (I'm on 1.1.2 and Python 2.65) and something has changed. I get an error: Exception Type: TypeError Exception Value: 'InMemoryUploadedFile' object is unsubscriptable

My code is:

Models.py:

from django.db import models
from django.contrib.auth.models import User
from django import forms
from datetime import datetime

class PhotoUrl(models.Model):
url = models.CharField(max_length=128)
uploaded = models.DateTimeField()

def save(self):                                                                             
    self.uploaded = datetime.now()
    models.Model.save(self)

views.py:

import mimetypes
from django.http import HttpResponseRedirect
from django.shortcuts import render_to_response
from django.core.urlresolvers import reverse
from django import forms
from django.conf import settings
from boto.s3.connection import S3Connection
from boto.s3.key import Key

def awsdemo(request):   
def store_in_s3(filename, content):
    conn = S3Connection(settings.AWS_ACCESS_KEY_ID, settings.AWS_SECRET_ACCESS_KEY)
    b = conn.create_bucket('almacmillan-hark')
    mime = mimetypes.guess_type(filename)[0]
    k = Key(b)
    k.key = filename
    k.set_metadata("Content-Type", mime)
    k.set_contents_from_strong(content)
    k.set_acl("public-read")

photos = PhotoUrl.objects.all().order_by("-uploaded")
if not request.method == "POST":
    f = UploadForm()
    return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

f = UploadForm(request.POST, request.FILES)
if not f.is_valid():
    return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

file = request.FILES['file']
filename = file.name
content = file['content']
store_in_s3(filename, content)
p = PhotoUrl(url="http://almacmillan-hark.s3.amazonaws.com/" + filename)
p.save()
photos = PhotoUrl.objects.all().order_by("-uploaded")   
return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

urls.py:

(r'^awsdemo/$', 'harkproject.s3app.views.awsdemo'), 

awsdemo.html:

<div class="form">
    <strong>{{form.file.label}}</strong>
    <form method="POST" action ="." enctype="multipart/form-data">
        {{form.file}}<br/>
        <input type="submit" value="Upload">
    </form> 
</div>  

I'd really appreciate help. I hope I have provided enough code.

Kind regards AL

+1  A: 

I think your problem is this line:

content = file['content']

From the Django docs:

Each value in FILES is an UploadedFile object containing the following attributes:

  • read(num_bytes=None) -- Read a number of bytes from the file.
  • name -- The name of the uploaded file.
  • size -- The size, in bytes, of the uploaded file.
  • chunks(chunk_size=None) -- A generator that yields sequential chunks of data.

Try this instead:

content = file.read()
Jack M.
A: 

Have you tried Django Storages? That way you only have to specify a storage backend (s3boto in this case) either as the default storage backend, or supply it as an argument to a FileField or ImageField class.

Dick