Note my question is not regarding !=
but |=
A usage example is here
I assume that x |= y
is the same as x = x | y
but I could not find confirming documentation and wanted to be sure
Thanks
Note my question is not regarding !=
but |=
A usage example is here
I assume that x |= y
is the same as x = x | y
but I could not find confirming documentation and wanted to be sure
Thanks
It's a bitwise "or" plus assignment, so you are quite correct in your assumption.
Yes, it's a bitwise inclusive or assignment: http://www.cafeaulait.org/course/week2/03.html
More correctly, x |= y is actually computed as x = x | (y).
Here is an interesting example of why this is important.
int c = 2;
c %= c++ * ++c;
The interesting consequence here is that it would be written as
c = c % (c++ * ++c);
Java specifications tell us that the JVM will see the initial c first and store it, anything preceding it will have no effect on it, thus c++ & ++c will not actually affect the outcome of the calculation. It will always be c = 2 % which equals 2 :)