Hi
I want to do something similar to this
x = [1,2,3,4,5,6,7,8,9,0]
x
[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
y = [1,3,5,7,9]
y
[1, 3, 5, 7, 9]
y-x which shouel give [2,4,6,8,0]
But this is not supported in python list What is the best way of doing it?
Hi
I want to do something similar to this
x = [1,2,3,4,5,6,7,8,9,0]
x
[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
y = [1,3,5,7,9]
y
[1, 3, 5, 7, 9]
y-x which shouel give [2,4,6,8,0]
But this is not supported in python list What is the best way of doing it?
Use set difference
>>> z = list(set(x) - set(y))
>>> z
[0, 8, 2, 4, 6]
Or you might just have x and y be sets so you don't have to do any conversions.
That is a "set subtraction" operation. Use the set data structure for that.
In Python 2.7:
x = {1,2,3,4,5,6,7,8,9,0}
y = {1,3,5,7,9}
print x - y
Use a list comprehension:
[item for item in x if item not in y]
If you want to use the -
infix syntax, you can just do:
class MyList(list):
def __init__(self, *args):
super(MyList, self).__init__(args)
def __sub__(self, other):
return self.__class__(*[item for item in self if item not in other])
you can then use it like:
x = MyList(1, 2, 3, 4)
y = MyList(2, 5, 2)
z = x - y
But if you don't absolutely need list properties (for example, ordering), just use sets as the other answers recommend.