GET DIR URL of current script

Question

This is current script url : localhost/do/index.php -> I want a var or function that return localhost/do :) (something like $_SERVER['SERVER_NAME'].'/do');

Answer 1

Try:

$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
print_r($parts);

EDIT:

$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
$dir = $_SERVER['SERVER_NAME'];
for ($i = 0; $i < count($parts) - 1; $i++) {
 $dir .= $parts[$i] . "/";
}
echo $dir;

This should return localhost/do/

Answer 2

php has many functions for string parsing which can be done with simple one-line snippets
dirname() (which you asked for) and parse_url() (which you need) are among them

<?php

echo "Request uri is: ".$_SERVER['REQUEST_URI'];
echo "<br>";

$curdir = dirname($_SERVER['REQUEST_URI'])."/";

echo "Current dir is: ".$curdir;
echo "<br>";

address bar in browser is

http://localhost/do/index.php

output is

Request uri is: /do/index.php
Current dir is: /do/

Answer 3

dirname will give you the directory portion of a file path. For example:

echo dirname('/path/to/file.txt');  // Outputs "/path/to"

Getting the URL of the current script is a little trickier, but $_SERVER['REQUEST_URI'] will return you the portion after the domain name (i.e. it would give you "/do/index.php").

Answer 4

If you want to include the server name, as I understood, then the following code snippets should do what you are asking for:

$result = $_SERVER['SERVER_NAME'] . dirname(__FILE__);

$result = $_SERVER['SERVER_NAME'] . __DIR__; // PHP 5.3

$result = $_SERVER['SERVER_NAME'] . '/' . dirname($_SERVER['REQUEST_URI']);

Answer 5

$_SERVER['SERVER_NAME'] . dirname($_SERVER['REQUEST_URI']);