I've been using Spring Security 3.0 for our website login mechanism using a dedicated login webpage. Now I need that login webpage to instead be a lightbox/popup window on every webpage in our site where upon logging in I get an AJAX result whether it was successful or not. What's the best way to go about this with Spring Security and Spring webmvc 3.0?
A:
At the client-side you may simulate a normal form submission to your login url via ajax. For example, in jQuery:
$.ajax({
url: "${pageContext.request.contextPath}/j_spring_security_check",
type: "POST",
data: $("#loginFormName").serialize(),
beforeSend: function (xhr) {
xhr.setRequestHeader("X-Ajax-call", "true");
},
success: function(result) {
if (result == "ok") {
...
} else if (result == "error") {
...
}
}
});
At the server side, you may customize AuthenticationSuccessHandler and AuthenticationFailureHandler to return a value instead of redirect. Because you probably need a normal login page as well (for attempt to access a secured page via direct url), you should tell ajax calls from normal calls, for example, using header:
public class AjaxAuthenticationSuccessHandler implements AuthenticationSuccessHandler {
private AuthenticationSuccessHandler defaultHandler;
public AjaxAuthenticationSuccessHandler(AuthenticationSuccessHandler defaultHandler) {
this.defaultHandler = defaultHandler;
}
void onAuthenticationSuccess(HttpServletRequest request,
HttpServletResponse response, Authentication auth) {
if ("true".eqauls(request.getHeader("X-Ajax-call")) {
response.getWriter().print("ok");
response.getWriter().flush();
} else {
defaultHandler.onAuthenticationSuccess(request, response, auth);
}
}
}
axtavt
2010-08-10 00:02:20