extract digits between 2 patterns awk/egrep

Question

I want to extract the variable # of digits between two patterns, eg:

correction: blah blah.... AAM #6,blah blah

blah blah.... AAM #10 , blah blah

blah blah.... AAM #100 , blah blah

output: 6, 10 and 100

I need to extract numbers between "AMA #" and comma

Answer 1

try a regular expression like (?<=#)\d+

Answer 2

Assuming the two patterns the digits are supposed to be between are AAM# and ,

gawk 'match($0, /AAM #([[:digit:]]+)[[:space:]]*,/, a) {print a[1]}'

Answer 3

No need to use sed if you use awk. Its redundant.

gawk 'BEGIN{FS="/"}/COMPLETED/{
  match($7, /AAM #([[:digit:]]+)[[:space:]]?,/, a)
  printf "%s %s:%s \n", substr($4,1,10),substr($6,8,1),  a[1] 
} ' file