preg_replace("/(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)/i", '$1#$2$3', $somevar);
It's meant to turn, for example, PHP into #PHP.
Warning: preg_replace(): Unknown modifier '|'
HALP
preg_replace("/(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)/i", '$1#$2$3', $somevar);
It's meant to turn, for example, PHP into #PHP.
Warning: preg_replace(): Unknown modifier '|'
HALP
The first character in the regular expression is the delimiter. If you need to use this inside your regular expression then you need to escape it:
"/(\/s|^)...
^
Or alternatively, choose another delimiter that isn't used anywhere in your regular expression so that you don't need to escape:
"~(/s|^)...(/s|$)~i"
I prefer to do the latter as it makes the regular expression more readable.
(Although as NullUserException points out, the actual error is that you should have used a backslash instead of a slash).
It's because you are using the forward slash (/
) as your delimiter. When the regex engine gets to /s
(3rd character) it thinks the regex is over and the rest of it are modifiers. But no such modifier (|
) exists, thus the error.
Next time, you can either:
Change your delimiters to something you won't use in your regex, ie:
preg_replace("!(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)!i", '$1#$2$3', $somevar);
Or escape those characters with a backslash, ie: "/something\/else/"
*
I also suspect you didn't intend to use /s
, but the escape character \s
that matches whitespace characters.