php, is int and GET or POST

Question

Hi,

why always i get false?

even in a this situation:

echo $_GET['id']; //3
if(is_int($_GET['id']))
    echo 'int';

Answer 1

Because $_GET['id'] is a string like other parts of query string. You are not converting it to integer anywhere so is_int return false.

Answer 2

why always i get false?

Because $_GET["id"] is a string, even if it happens to contain a number.

Your options:

• Use the filter extension. filter_input(INPUT_GET, "id", FILTER_VALIDATE_INT) will return an integer typed variable if the variable exists, is not an array, represents an integer and that integer is within the valid bounds. Otherwise it will return false.

• Force cast it to integer (int)$_GET["id"] - probably not what you want because you can't properly handle errors (i.e. "id" not being a number)

• Use is_numeric() that will correctly recognize the string not perfect: It will also recognize float values (1.23132)

• Use ctype_digit() to make sure the string consists only of numbers, and therefore is an integer - technically, this returns true also with very large numbers that are beyond int's scope, but I doubt this will be a problem. However, note that this method will not recognize negative numbers.

Answer 3

It's probably stored as a string in the $_GET, cast it to an int.

Answer 4

Because HTTP variables are always either strings, or arrays. And the elements of arrays are always strings or arrays.

You want the is_numeric function, which will return true for "4". Either that, or cast the variable to an int $foo = (int) $_GET['id']...

Answer 5

Because $_GET is an array of strings.

To check if the get parameter contains an integer you should use is_numeric()