How to create a regexp that matches a pattern except for some strings in Ruby?

Question

I work in Ruby, and have to create a single regexp for the following task, as I'm working with someone else's gem that uses this regexp to match fields to be worked on in a text file. I need to match beginning of string, any set of characters, and underscore, then any multi-digit integer that is not 1,2, 9, or 10, and end of string.
I.e., I want the following to match:

foo_4
bar_8
baz_120

BUT NOT:

foo_1
bar_9
baz_10

I tried

/^.+_(^(1|2|9|10))$/

but it did not work as apparently ^ only "negates" characters in brackets, not submatches.

Answer 1

Outside of a character class the ^ symbol means start of line. I think you want a negative lookahead instead:

/^.+_(?!(?:1|2|9|10)$)\d+$/

See it in action on rubular.

Answer 2

So, the ending integer has to be multi-digit, right? If that's the case, then you don't need to check for 1, 2, or 9, I would think. I'm trying to find the write expression, but I'm a newby at regular expressions.

Edit: nevermind as by the time I finished this you had edited your post. :)