Filter results for Django paginator in template

Question

I'm filtering out results from my page_obj in a generic view to only show entries published in the same language as the languge currently set by django-cms (http://www.django-cms.org/en/documentation/2.0/i18n/).

This works fine, but adding in support for Django pagination (http://docs.djangoproject.com/en/1.2/topics/pagination/) causes the filtered results to still be counted. So, for example when there are three results in English, from a total of ten results and pagination is set to 2, I'll get 5 result pages, most of which are of course blank becuse the filtering of the remaining seven is done in the template.

Can I amend Django Paginator to work with the filter in the template using a template tag, or do I have to rebuild my views? If so, how do I go about doing that?

The relevant code:

managers.py

def update_queryset(view, queryset, queryset_parameter='queryset'):
    '''Decorator around views based on a queryset passed in parameter, which will force the update of the queryset before executing the view.
    Related to issue: http://code.djangoproject.com/ticket/8378'''
    def wrap(*args, **kwargs):
        #Regenerate the queryset before passing it to the view.
        kwargs[queryset_parameter] = queryset()
        return view(*args, **kwargs)
    return wrap

views/entries.py

from django.views.generic.list_detail import object_list
from cmsplugin_publisher.models import Entry
from cmsplugin_publisher.managers import update_queryset

entry_index = update_queryset(object_list, Entry.published.all)

urls/entries.py

from django.conf.urls.defaults import *
from cmsplugin_publisher.models import Entry
from cmsplugin_publisher.settings import PAGINATION, ALLOW_EMPTY, ALLOW_FUTURE

entry_conf_list = {'queryset': Entry.published.all(), 'paginate_by': PAGINATION}

entry_conf = { 'queryset': Entry.published.all(),}

entry_conf_detail = entry_conf.copy()
entry_conf_detail['queryset'] = Entry.objects.all()

urlpatterns = patterns('cmsplugin_publisher.views.entries',
    url(r'^$', 'entry_index', entry_conf_list, name='cmsplugin_publisher_entry_archive_index'),
    url(r'^(?P<page>[0-9]+)/$', 'entry_index', entry_conf_list, name='cmsplugin_publisher_entry_archive_index_paginated'),
)

urlpatterns += patterns('django.views.generic.list_detail',
    url(r'^(?P<slug>[-\w]+)/$', 'object_detail', entry_conf_detail, name='cmsplugin_publisher_entry_detail'),
)

in entry_list.html

{% block content %}
    {% for object in object_list %}
      {% ifequal object.language current_language %}
        ..
      {% endifequal %}
    {% endfor %}
    {% if is_paginated %}
    <ul id="pagination">
    {% if page_obj.has_previous %}
        {% ifnotequal page_obj.start_index 1 %}<li><a href="../" title="{% trans 'View Latest Entries' %}">{% trans 'Latest Entries' %}</a></li>{% endifnotequal %}
        {% ifequal page_obj.previous_page_number 1 %}{% endifequal %}
        {% ifnotequal page_obj.previous_page_number 1 %}
            <li><a href="../{{ page_obj.previous_page_number }}/" title="{% trans 'View Earlier Entries' %}">{% trans 'Earlier Entries' %}</a></li>
        {% endifnotequal %}
    {% else%}
    {% endif %}
    <li>{% trans 'Page' %} {{ page_obj.start_index }} {% trans 'of' %} {{ paginator.num_pages }} {% trans 'Entries' %}</li>
    {% if page_obj.has_next %}
        {% ifnotequal page_obj.start_index 1 %}
            <li><a href="../{{ page_obj.next_page_number }}/" title="{% trans 'View Older Entries' %}">{% trans 'Older Entries' %}</a></li>
        {% endifnotequal %}
        {% ifequal page_obj.start_index 1 %}
        <li><a href="{{ page_obj.next_page_number }}/" title="{% trans 'View Older Entries' %}">{% trans 'Older Entries' %}</a></li>
        {% endifequal %}
    {% else%}
    {% endif %}
    </ul>
{% endif %}

I'd appreciate any light you guys can throw on the best solution here.

Answer 1

The soultion, ultimately, was to rebuild the views. Extensive rebuilding required in this case.

Moral of the sory: don't filter in templates!