tags:

views:

29

answers:

2
+1  Q: 

How to create MUC and send messages to existing MUC using Python and XMPP

I was wondering if anyone here can provide some code samples on the following scenarios. I'm particularly interested in using xmpppy to do this as I'm already using the library for my app, but other libraries ok too. It is unfortunate that the xmpppy project website doesn't have any samples on this. Browsing the expert/advanced API docs, I couldn't figure out how to do it, or is multi-user chat (MUC) not supported with xmpppy?

  • create a MUC by inviting specific users (say 2 or 3)

  • send message to an existing MUC (assuming you know it's MUC JID handle or nickname)

  • look up existing MUCs on the XMPP server, getting the JID or nickname, etc. If this is done by getting roster, we want to only look for MUCs, ignoring users.

I found sort of an answer here, but then I'd probably have to learn new library API calls and figure out how to do my above mentioned scenarios as this sample doesn't cover all of them:

http://stackoverflow.com/questions/2364039/pyxmpp-quick-tutorial-for-creating-a-muc-client

I'm really looking to do a load generator that pumps messages to MUCs and creating large MUCs with many participants. I've already got the part in place for pumping messages to user recipients.

A: 

While I dont know about specific MUC interface there, xmpppy supports custom messages, so it supports whole XMPP.

To join chat, you need to send presence stranza, conn.send(xmpp.Presence(to='{0}/{1}'.format(room, nick)))

To send a message to chat: 

    stranza = "<message to='{0}' type='groupchat'><body>{1}</body></message>".format(room, text)
    conn.send(stranza)

As for creating new chat or looking it up in roster, I don't have ready code at hand, but it is easy to write in the same fashion, just look up needed stranzas in XEPs:

http://xmpp.org/extensions/xep-0045.html#createroom

http://xmpp.org/extensions/xep-0045.html#disco-rooms

http://xmpp.org/extensions/xep-0045.html#invite

Daniel Kluev  2010-08-20 07:09:49
A: 

Xmpppy does support using MUC services, but the support is very basic and some extra code will be needed to manage multiple rooms.

To "join" a MUC room you need to broadcast your presence to the JID.

conn.send(xmpp.Presence(to="%s/%s" % (room, nickname)))

Then to send messages, you send them using the 'groupchat' message type to the room JID.

msg = xmpp.protocol.Message(body=text)
msg.setTo(room)
msg.setType('groupchat')
conn.send(msg)

As for your question regarding finding MUC rooms, that'll be done via service discovery.

Andrew Williams  2010-08-23 10:27:58

related questions

Programmatically talking to a Serial Port in OS X or Linux
Best ways to teach a beginner to program?
Calling a Function From a String With the Function's Name in Python
An executable Python app
Text Editor For Linux (Besides Vi)?
What Hosting Service is best for Django applications?
File size differences after copying a file to a server vía FTP
Python: what is the difference between (1,2,3) and [1,2,3], and when should I use each?
Python: What OS am I running on?
How do I make a menu in python that does not require the user to press (enter) to make a selection?
How do you express binary literals in Python?
What is the most efficient graph data structure in Python?
Adding a Method to an Existing Object
How to learn Python: Good Example Code?
How do I use Python's itertools.groupby()?
Python and MySQL
Class views in Django
Is there an IDE that provides code completion for Python
Using 'in' to match an attribute of Python objects in an array
cx_Oracle - what is the best way to iterate over a result set?
cx_Oracle - How do I access Oracle from Python?
Continuous Integration System for a Python Codebase
Get a preview jpeg of a pdf on windows?
How can I find the full path to a font from its display name on a Mac?
XML Processing in Python