I hope I asked that correctly. I am trying to figure out what element.sourceline does and if there is some way I can use its features. I have tried building my elements from the html a number of ways but every time I iterate through my elements and ask for sourceline I always get None. When I tried to use the built-in help I done't get anything either.
I have Googled for an example but none were found yet.
I know it is a method of elements not trees but that is the best I have been able to come up with.
In response to Jim Garrison's request for an example
theTree=html.parse(open(r'c:\temp\testlxml.htm'))
check_source
the_elements=[(e,e.sourceline) for e in theTree.iter()] #trying to get the sourceline
for each in the_elements:
if each[1]!=None:
check_source.append(each)
When I run this len(check_source)==0
My htm file has 19,379 lines so I am not sure you want to see it
I tried one solution
>>> myroot=html.fromstring(xml)
>>> elementlines=[(e,e.sourceline) for e in myroot.iter()]
>>> elementlines
[(<Element doc at 12bb730>, None), (<Element foo at 12bb650>, None)]
When I do the same thing with etree I get what was demonstrated
>>> myroot=etree.fromstring(xml)
>>> elementlines=[(e,e.sourceline) for e in myroot.iter()]
>>> elementlines
[(<Element doc at 36a6b70>, 1), (<Element foo at 277b4e0>, 2)]
But my source htm is so messy I can't use etree to explore the tree I get an error