Hello all,
Please excuse this novice question, but I'm ramping up on Silverlight and MVVM Light. I created a view called MyView.xaml and a corresponding MyViewModel.cs.
MyView.xaml
<navigation:Page x:Class="Dashboard.Views.MyView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:vm="clr-namespace:Dashboard.ViewModels"
xmlns:controls="clr-namespace:Dashboard.Controls"
mc:Ignorable="d"
xmlns:navigation="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Navigation"
d:DesignWidth="640" d:DesignHeight="480"
Title="MyView Page" xmlns:toolkit="http://schemas.microsoft.com/winfx/2006/xaml/presentation/toolkit">
<navigation:Page.Resources>
<vm:MyViewModel x:Key="MyViewModel" />
</navigation:Page.Resources>
<navigation:Page.DataContext>
<Binding Source="{StaticResource MyViewModel}"/>
</navigation:Page.DataContext>
<Grid x:Name="LayoutRoot">
<StackPanel Orientation="Vertical" Style="{StaticResource LoginControlsStackPanelStyle}" HorizontalAlignment="Center" VerticalAlignment="Center">
<toolkit:DataForm Name="dataForm1" CurrentItem="{Binding}"/>
</StackPanel>
</Grid>
MyViewModel.cs
namespace Dashboard.ViewModels
{
public class MyViewModel : ViewModelBase
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
}
When I run the project, my form renders the IsInDesignMode property. I obviously do not want this. How can I prevent the base class property from rendering in the dataform?
Thanks.
Andrew