How to write a ruby regex that removes characters only at first and last positions?

Question

I have a log file, most lines are quoted at first and last character, like:

 "2010-09-09,13:33,"user logoff",0"

What's the ruby regex to remove the head and tail quotation marks? so the result string looks like:

 2010-09-09,13:33,"user logoff",0

Answer 1

str.gsub /^"|"$/, ''

Answer 2

Or without regular expressions:

string[1...-1]