I have this:
Lt = [('ABC', ), ('Abc', ), ('xyz', ), ('ABC', ), ('Abc', )]
I want this:
Lt = ('Abc', 'Abc', 'xyz', 'ABC', 'ABc')
remove the extra "(",")" and ",".... How do i do this.
views:
68answers:
2
+5
A:
Is that a list of strings or tuples? Assuming they're tuples:
[t[0] for t in [('ABC', ), ('Abc', ), ('xyz', ), ('ABC', ), ('Abc', )]]
Falmarri
2010-09-08 22:23:47
+1 Nice and elegant
Helper Method
2010-09-08 22:28:19
For the sake of learning, this is called a "list comprehension" and thy are very efficient and easy to do in Python!
jathanism
2010-09-08 22:28:21
didnt work, thk
2010-09-08 22:28:43
@user, just apply `tuple`
aaronasterling
2010-09-08 22:30:34
It gives me the last ('Abc',) missing everything else
2010-09-08 22:35:44
[('ABC',), ('Abc',), ('xyz',), ('ABC',), ('Abc',)]>>> [t[0] for t in [('ABC', ), ('Abc', ), ('xyz', ), ('ABC', ), ('Abc', )]]['ABC', 'Abc', 'xyz', 'ABC', 'Abc']
João Pinto
2010-09-08 22:54:49
@user428862: Could you be mistyping something perhaps? Because the code does work (I just copied it into my Python shell to verify).
David Zaslavsky
2010-09-08 22:56:11
@user: You probably have the `[]` in the wrong place
Falmarri
2010-09-08 23:15:52
A:
another way
a = tuple([''.join(x) for x in Lt])
>>> a
('ABC', 'Abc', 'xyz', 'ABC', 'Abc')
momo
2010-09-08 22:47:12
You can remove the square brackets in the call to `tuple`. a generator expression suffices because `tuple` will consume it.
aaronasterling
2010-09-08 23:09:05