problem with values in php - begginer

Question

Hi! when the row['error'] is bigger than 35, the value isn't present and the result of the function is 0. can you pls tell me where is the problem?

<?php

if($row['error'] == "")
{
    $error="0";
}
else
{
    $error=$row['error'];
}

if($row['error'] != "")
{
   if(strlen($error) > 35)
       {
       $error = substr($row['error'],0,32) + "...";
       }
       else
       {
       $error = $row['error'];
       }
}  ?>

Answer 1

Change

$error = substr($row['error'],0,32) + "...";

to:

$error = substr($row['error'],0,32) . "...";

The concatenate operator in PHP isn't a plus (+) sign; it's a period (.) sign

Answer 2

Because you check:

if(strlen($error) > 35) {
}

Answer 3

Why all this code? Second condition is redundant, it doubles else condition from above
why not to make it all with just these few lines?

<?php
$error = $row['error'];
if(strlen($error) > 35) {
  $error = substr($row['error'],0,32) . "...";
}
?>