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CakePHP: using models in different controllers

Answer 1

+4 A:

You must load every model in the controller class by variable $uses, for example:

var $uses = array('Project');

or in action use method

$this->loadModel('Project');

Tomasz Kowalczyk 2010-09-12 21:31:01

If you are satisfied with mi answer, please accept ;]

Tomasz Kowalczyk 2010-09-12 21:33:08

if seems to have worked thanks! one more question though would I use it in the view like so: foreach($projects as $project){ echo $project['title']; echo '<br />'; } because it's telling me title is undefined

iamjonesy 2010-09-12 21:37:48

I can't tell you this now because I don't have code to run now, but please var_dump() the content that is being returned by find() and see where exactly is 'title' located in tree.

Tomasz Kowalczyk 2010-09-12 21:39:45

got it foreach($projects as $project){ echo $project['Project']['title']; echo '<br /><br />'; }

iamjonesy 2010-09-12 21:47:40

Answer 2

A:

For me it's more reasonable to use requestAction. This way the logic is wrapped in the controller.

In example:

//in your controller Projects:

class ProjectsController extends AppController {
  function dashboard(){
    $this->set('projects', $this->Project->find('all'));
  }
  $this->render('dashboard');
}

Bear in mind that you need to create dashboard.ctp in /app/views/projects of course.

In the Page's dashboard view (probably /app/views/pages/dashboard.ctp) add:

echo $this->requestAction(array('controller'=>'projects', 'action'=>'dashboard'));

This way the logic will remain in the project's controller. Of course you can request /projects/index, but the handling of the pagination will be more complicated.

more about requestAction(). but bear in mind that you need to use it carefully. It could slow down your application.

Nik 2010-09-13 13:46:07

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CakePHP: using models in different controllers

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