Jquery vs PHP - load an image into a div

Question

Hi. i'm looking for a php script server side that load an image in a div on client side.

first shot : ajax.php

if((isset($_POST['id'])) && ($_POST['id']=="loadphoto") && (ctype_digit($_POST['idp']))) {
    $query=mysql_query("SELECT articleid, photoid FROM articles_photos WHERE id='".$_POST['idp']."'", $mydb);
    if(mysql_num_rows($query)!=0){
        while($row=mysql_fetch_array($query, MYSQL_NUM)) {
            $path="./articles/photos/".$row[0]."/".$row[1];
        }

        echo $path;
    }
}

myjs.js

function loadPhoto(mexid) {
$.ajax({
    type: 'POST',
    cache: false,
    url: './auth/ajax.php',
    data: 'idp='+escape(mexid)+'&id=loadphoto',
    success: function(msg) {
        $('.articleviewphoto1').find("img").each(function(){
            $(this).removeClass().addClass('photoarts');
        });

        $('#'+mexid).removeClass().addClass('photoartsb');
        $('#visualizator').html('<img src="'+msg+'" class="photoartb" />');
    }
});
return false;

}

tnx for the helps

Answer 1

Using the PHP GD Library

Answer 2

I'm assuming the image already exists somewhere and isn't being generated on the fly. In the PHP script, you can access the variables with $_POST['idp'] and $_POST['id']. Do whatever processing you need, and then simply echo the URL. The variable msg in the javascript will be everything echo'd by the PHP script. Then, you could just do this:

$('#visualizator').html('<img src="' + msg + '" />');

Answer 3

Are you looking to host a list of possible images in the PHP file and load different images based on the id you send? If so, you can set:

$Img = $_POST['idp'];

And use a switch statement to pass back the image file path:

switch ($Img){
  case (some_value):
      echo 'images/some_file.jpg';
      break;

  case (another_value):
      echo 'images/another_file.jpg';
      break;

}

Then place the file path in an tag and load that into $('#visualizator').html();

Am I on track at least with what you want? If so, I can flesh the answer out a bit.