How do I assign a numerical value to each uppercase Letter?

Question

How do i assign a numerical value to each uppercase letter, and then use it later via string and then add up the values.

EG.

A = 1, B = 2, C = 3 (etc..)

string = 'ABC'

Then return the answer 6 (in this case).

Answer 1

You can use ord to get the ascii code, then subtract 64.

def codevalue(char):
    return ord(char) - ord('A')

Answer 2

import string

letter_to_numeral = dict(zip(string.uppercase, range(1, len(string.uppercase) + 1) ))

print letter_to_numeral
>>> {'A': 1, 'C': 3, 'B': 2, 'E': 5, 'D': 4, 'G': 7, 'F': 6, 'I': 9, 'H': 8, 'K': 11, 'J': 10, 'M': 13, 'L': 12, 'O': 15, 'N': 14, 'Q': 17, 'P': 16, 'S': 19, 'R': 18, 'U': 21, 'T': 20, 'W': 23, 'V': 22, 'Y': 25, 'X': 24, 'Z': 26}

def score_string(s):
    return sum([letter_to_numeral[character] for character in s])


score_string('ABC')
>>> 6

Answer 3

def getvalue(mystring):
    letterdict = dict(zip('ABCDEFGHIJKLMNOPQRSTUVWXYZ',range(1,27)))
    return sum(letterdict[c] for c in mystring)

Answer 4

base = ord('A') - 1
mystring = 'ABC'
print sum(ord(char) - base for char in mystring)

Answer 5

After you define the variables you can just return the answer or print the answer A = 1 B = 2 C = 3 total = A + B + C print (total) return total

Answer 6

Enumerate can do the numbering for you:

import string
numerology_table = dict((ch,num+1) for (num,ch) in enumerate(string.ascii_letters[:26].upper()))

Answer 7

If you are using Python3:

result = 0
mystring = 'ABC'
for char in mystring.encode('ascii'):
    result += char - 64

>>> result
6

Answer 8

Golfy answer certain to annoy your professor:

>>> s = 'ABC'
>>> sum(map(ord,s),-64*len(s))
6

Answer 9

The most sensible answer is of course using ord as shown earlier. But for those who chose to construct a dictionary, I would rather just use the index in the string:

>>> import string
>>> mystring = 'ABC'
>>> sum(string.uppercase.index(c) + 1 for c in mystring)
6