Ruby: what is the best way to find out method type in method_missing?

Question

At the moment I've got this code:

name, type = meth.to_s.match(/^(.+?)([=?]?)$/)[1..-1]

But it doesn't seem to be the best solution =\

Any ideas how to make it better? Thanks.

Answer 1

The best option seems to be this: name, type = meth.to_s.split(/([?=])/)

Answer 2

This is roughly how I'd implement my method_missing:

def method_missing(sym, *args, &block)
  name = sym.to_s
  if name =~ /^(.*)=$/
    # Setter method with name $1.
  elsif name =~ /^(.*)\?$/
    # Predicate method with name $1.
  elsif name =~ /^(.*)!$/
    # Dangerous method with name $1.
  else
    # Getter or regular method with name $1.
  end
end

Or this version, which only evaluates one regular expression:

def method_missing(sym, *args, &block)
  name = sym.to_s
  if name =~ /^(.*)([=?!])$/
    # Special method with name $1 and suffix $2.
  else
    # Getter or regular method with name.
  end
end