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7433

answers:

6

Hi,

How can I get the file name from a file path in Ruby?

For example if I have a path of "C:\projects\blah.dll"

and I just want the blah.

Is there a LastIndexOf function in Ruby?

Thanks

Paul

+33  A: 

Try File.basename

Returns the last component of the filename given in file_name, which must be formed using forward slashes (``/’’) regardless of the separator used on the local file system. If suffix is given and present at the end of file_name, it is removed.

File.basename("/home/gumby/work/ruby.rb")          #=> "ruby.rb"
File.basename("/home/gumby/work/ruby.rb", ".rb")   #=> "ruby"

In your case:

File.basename("C:\\projects\\blah.dll", ".dll")  #=> "blah"
Jonathan Lonowski
With Linux and Ruby 1.8 I try `Pathname.new("some/path/to/my.file").basename` and get `my.file/` :'(
java.is.for.desktop
+2  A: 

Note that double quotes strings escape \'s.

'C:\projects\blah.dll'.split('\\').last
krusty.ar
+4  A: 

Jonathon's answer is better, but to let you know somelist[-1] is one of the LastIndexOf notations available.

(As krusty.ar mentioned somelist.last apparently is too!)

irb(main):003:0* f = 'C:\\path\\file.txt'
irb(main):007:0> f.split('\\')
=> ["C:", "path", "file.txt"]
irb(main):008:0> f.split('\\')[-1]
=> "file.txt"
monkut
+8  A: 

irb(main):007:0> require 'pathname'
irb(main):007:0> Pathname.new('/opt/local/bin/ruby').basename
=> #<Pathname:ruby>

Not a windows user in a long time, but the Pathname rdoc says it has no issues with directory name separators on windows.

korch
+5  A: 

In case the extension is not known (it needs the / separator):

irb(main):024:0> f = 'C:\foobar\blah.txt'.gsub("\\","/")
=> "C:/foobar/blah.txt"
irb(main):027:0> File.basename(f,File.extname(f))
=> "blah"
Vinko Vrsalovic
A: 

If you have access to ENV variables, scan combined with this little regex (which finds the last but one word, a dot, then the last word of the string) will put the file's name into 'filename':

filename = ENV['SCRIPT_NAME'].scan(/\w+\.\w+$/)

Obviously, you can use scan and the regex on any path name that includes the filename, and __FILE__ is the obvious choice:

__FILE__.scan(/\w+\.\w+$/)
Dave Everitt