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Answer 1

A:

Do you mean that you want to iterate through each of the eight JSONObjects in this JSONArray? You need to create a JSONArray object with the input string you posed above (let's call it "response", as used below) and then iterate through the array to get each JSONObject it contains. For example:

JSONArray array = new JSONArray(response);
for(int i = 0; i < array.length(); i++) {
    JSONObject obj = array.getJSONObject(i);

    // do something with obj
    // example: to get the id for a particular object, use obj.getString("id")
    Log.i("Example", "the id is"+obj.getString("id"));
}

cfei 2010-09-20 16:22:44

thanks,may be i did not specify the quetions,sorry for that

peter_feng 2010-09-22 03:04:06

Answer 2

A:

To add to cfei's response, one thing that I've done when processing JSON responses from Flickr, is create a new class particularly for that type of object.

So for yours, just playing it by ear, something like the below:

public class Lottery() {
    private JSONObject json;
    private String id;
    private String name;
    private String term;
    private String date;
    private String norm_numbers;
    private String spec_numbers;
    private String jackpot;

    public Lottery(JSONObject json) {
        this.json = json;
    }
    public void setId()
    {
        try {
            id = json.getString("id");
        } catch (JSONException e) {
            id = "";
        }
    }
    //additional getters and setters, etc.
}

This way, you can make an array of objects, and access the fields like so:

//...get a JSONObject from the array...
Lottery lottery = new Lottery(json);
Log.v("ID", lottery.id);
Log.v("Name", lottery.name);

and so on.

kcoppock 2010-09-20 18:29:05

thank you for you answer

peter_feng 2010-09-22 03:05:02

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