I want to split a string suppressing all null fields
Command:
",1,2,,3,4,,".split(',')
Result:
["", "1", "2", "", "3", "4", ""]
Expected:
["1", "2", "3", "4"]
How to do this?
Edit
Ok. Just to sum up all that good questions posted.
What I wanted is that split method (or other method) didn't generate empty strings. Looks like it isn't possible.
So, the solution is two step process: split string as usual, and then somehow delete empty strings from resulting array.
The second part is exactly this question (and its duplicate)
So I would use
",1,2,,3,4,,".split(',').delete_if(&:empty?)
The solution proposed by Nikita Rybak and by user229426 is to use reject method. According to docs reject returns a new array. While delete_if method is more efficient since I don't want a copy. Using select proposed by Mark Byers even more inefficient.
steenslag proposed to replace commas with space and then use split by space:
",1,2,,3,4,,".gsub(',', ' ').split(' ')
Actually, the documentation says that space is actually a white space. But results of "split(/\s/)" and "split(' ')" are not the same. Why's that?
Mark Byers proposed another solution - just using regular expressions. Seems like this is what I need. But this solution implies that you have to be a master of regexp. But this is great solution! For example, if I need spaces to be separators as well as any non-alphanumeric symbol I can rewrite this to
",1,2, ,3 3,4 4 4,,".scan(/\w+[\s*\w*]*/)
the result is:
["1", "2", "3 3", "4 4 4"]
But again regexps are very unintuitive and they need an experience.
Summary
I expect that split to work with whitespaces as if whitespaces were a comma or even regexp. I expect it to do not produce empty strings. I think this is a bug in ruby or my misunderstanding.
Made it a community question.