How do i find the calling file location?

Question

Hi guys,

I am trying to locate the location of file being displayed in php.

I have a small file which can be included by any file wither from root or from inside any folder.

i need to print out the location of the.

for long explanation: my config file is config.php located in root location of website i.e localhost/site1/test/. It contains print $_SERVER['SCRIPT_NAME']. it is being included by index.php in root location and also by database.php inside the includes folder of root.

I get two different result:

1. localhost/site1/test/, when i include config.php in index.php

2. localhost/site1/test/includes, when i include config.php in database.php

I would like to get localhost/site1/test in both cases. So what can be the choice instead $_SERVER['SCRIPT_NAME']

Answer 1

Try dirname(__FILE__) (or __DIR__ if using PHP >= 5.3).

http://php.net/manual/en/language.constants.predefined.php

Answer 2

Try this: print_r($_SERVER) you will surely find what you are looking for in that array.

Update:

<?php
print_r($_SERVER['HTTP_HOST'].'/'.$_SERVER['SCRIPT_NAME']);
?>