copy all fields of a django model instance

Question

Hello everybody,

ok i think this is very basic, but since i'm new to django i don't know how to handle this.. I need to copy an instance of a django-model. As explained here, there is a problem with copying many2many relations. But the attachment "django-model-copying.diff" has that function i guess. So i don't know - does my django already have that function? I don't know how to call it.. Help would be appreciated :)

thanks in advance!

Answer 1

You can just do the following:

m = MyModel.objects.get(pk=1)
m.id = None
m.save()

That way new instance will be created with new id of course in case of any unique properties it will trigger errors during validation.

NOTE: As for the function you've mentioned - it is not yet added to the trunk, the status is design decision needed, but if you know what you're doing you can manually apply the diff to your django instance - it's called patching btw. Here are some details about how to do it: http://ariejan.net/2007/07/03/how-to-create-and-apply-a-patch-with-subversion/.