jQuery: but what about all the children!?

Question

I feel like I have to use way too many .children() in some of my jQuery functions.

Here's my HTML:

<div class="goal-small-container">
  <div class="goal-content">
    <div class="goal-row">
      <span class="goal-actions">

And here's my jQuery:

$('.goal-small-container').hover(function() {
  $(this).children('.goal-content').children('.goal-row').children('.goal-actions').css({visibility: "visible"});
}, function () {
  $(this).children('.goal-content').children('.goal-row').children('.goal-actions').css({visibility: "hidden"});
});

Is there a better way? Tell me for the kids.

Answer 1

have you heard about .find() ?

$('.goal-small-container').hover(function() {
  $(this).find('.goal-actions').css({visibility: "visible"});
}, function () {
  $(this).find('.goal-actions').css({visibility: "hidden"});
});

Answer 2

Instead of

$(this).children('.goal-content').children('.goal-row').children('.goal-actions').css({visibility: "visible"});

You can use:

$(this).children('.goal-content > .goal-row > .goal-actions').css({visibility: "visible"});

For exactly the same meaning. If there's no chance of that being ambiguous, however, (.goal-actions will only appear in that structure of the markup) you can just use find.

Answer 3

.find('.goal-content .goal-row .goal-action').whatever()

or more simply:

.find('.goal-action').whatever()

Answer 4

Why don't you just use .show() and .hide() on the second <div>? And, initially have them display hidden or something.

Answer 5

You can just use:

$('.goal-small-container').hover(function() {
   $(this).find('goal-actions').show();
}, function() {
   $(this).find('goal-actions').hide();
});