Unable to perform any PHP operations in an Ajax application.

Question

My Ajax application was working fine, until I implemented an if statement in the PHP script... then like a contagious disease it seems that if I do anything to the data in PHP it returns nothing back to the Javascript layer.

All I can do is echo the data back...

For instance the query string I'm sending to the PHP reads...

index.back3.php?form=login&json={"email":"[email protected]","password":"asdasdfas"}

and I know its getting there because in the simplest debugging PHP file (index.back3.php) that I created all I have is a simple echo statement... and it never fails to send back the data to the Javascript file.

when index.back3.php reads

<?php echo $_GET[json]; ?>

the alert that I have triggering off in the javascript reliably spits out the json string.

also when it reads

<?php echo $_GET[form]; ?>

when I get any more complicated than that nothing comes back to the javascript. Even a simple concatenation...

<?php echo ($_GET[form] . $_GET[json]); ?>

...returns nothing!

A simple if...else statement also returns nothing.

<?php

    if(!isset($_GET[form]) { 
     echo "no!";
    } else {
     echo "yes!";
    }

?>

And this important operation also...

<?php

 $array = json_decode($GET[json], true);

 var_dump($array);
?>

returns nothing.

OK... so just to make sure everything is above board here is my Ajax output function in the Javascript layer.

function responseAjax() {

 if (myRequest.readyState == 4)  {

  if(myRequest.status == 200) {  

   var foo = myRequest.responseText;

   alert(foo);

  } else {

   alert("An error has occured:  " + myRequest.statusText);
  }
 }
}

Can someone please explain what's going on? I'm truly stumped.

Answer 1

$_GET['form'] is the right way.

and using form as variable name is not at all good.

use anyother variable and pass $_GET['formname'].

Try to access the php page directly through url and pass the parameters , check first the php

return error or its working propelry.

You can use PHP , jquery and ajax in simple ways.

try to find .post or .get methods in jquery

http://api.jquery.com/jQuery.post/

$.post('ajax/test.html', function(data) { $('.result').html(data); });

Answer 2

I managed to sort it out, it had to do with a line of code which I omitted from this post, because I thought it was reduntant. The full version of the function went like this.

function responseAjax() {

    if (myRequest.readyState == 4)  {       

        if(myRequest.status == 200) {       

            var foo         =   myRequest.responseText;     

            var cookieData      =   eval("(" + foo + ")");  //this was the problem!!

            alert(foo);             

            document.cookie = 'email ='     + cookieData.email      + '; path=/';
            document.cookie = 'firstname =' + cookieData.FirstName  + '; path=/';

        } else {

            alert("An error has occured:  " + myRequest.statusText);
        }
    }
}

It was the 'var cookieData' line... though I'm not sure why.