Unix Sed to get lines from a last occurance of a given word

Question

I want to get the lines from a file from the line which contains the last occurance of a given word.

Ex:

True, there have been some
changes in the plot. In the original,
Kane tried to buy high political
office for himself. In the new version,
he just puts politicians on his payroll.

If I give "In" then I need

office for himself. In the new version,
he just puts politicians on his payroll.

Answer 1

Try:

grep 'yourWord' yourFile.txt | tail -n1

Or with sed:

sed -n '/yourWord/{$p}' yourFile.txt

Answer 2

$ word="In"
$ awk -vw="$word" '{s=s$0}END{ m=split(s,str,w); print w str[m]}' file
In the new version, he just puts politicians on his payroll.

I don't understand why there is "office for himself." though.

Answer 3

This should work:

As a one-liner:

patt=In
sed -nr "/$patt/!b;:a;\$!N;/\n.*$patt/{h;s/\n[^\n]*\$//;g;s/^.*\n//};\$!ba;p" inputfile

If your sed requires -e:

patt=In
sed -nr -e "/$patt/!b" -e ":a" -e "\$!N" -e "/\n.*$patt/{h" -e "s/\n[^\n]*\$//" -e "g" -e "s/^.*\n//}" -e "\$!ba" -e "p" inputfile

On separate lines:

patt=In
sed -nr "
    /$patt/!b
    :a
    \$!N
    /\n.*$patt/{
    h
    s/\n[^\n]*\$//
    g
    s/^.*\n//
    }
    \$!ba
    p' inputfile