It is NOT class variable but instance variable if you define/access it this way.
Most of the time in PHP, i forget including $ in variable name. Try as
$this->$res = "blah";
Atilla Ozgur
2010-10-08 11:51:40
A:
Are you sure about this?
fabrik
2010-10-08 11:53:01
+2
A:
You made a typo @
$x="blah" (missing ;)
Working code: http://ideone.com/jmICU
(Controller stripped out)
Please let me know if my answer has worked.
fabrik
2010-10-08 11:58:30
Oops.. that was a typo while filling in this forum.. thanks for pointing it out..
Shrinath
2010-10-08 12:21:46
I edited in http://ideone.com/brbGZ Check now.. It behaves as described in question
Shrinath
2010-10-08 12:22:27
Your example provided in your question is not the same as you wrote @ Ideone. The problem is you define `$res` as string then later you assign a variable to it as an array. Please take a look @ http://ideone.com/0ayLi now it works again.
fabrik
2010-10-08 12:25:41
works :) as you said, I shouldn't have initialized it to string.. or atleast, not to character '' (it worked when I tried $res=""). Cool man, if I had enough rep to give you a vote, i'd have :) thanks..
Shrinath
2010-10-08 12:40:33