How do I count words in an nltk plaintextcorpus faster?

Question

I have a set of documents, and I want to return a list of tuples where each tuple has the date of a given document and the number of times a given search term appears in that document. My code (below) works, but is slow, and I'm a n00b. Are there obvious ways to make this faster? Any help would be much appreciated, mostly so that I can learn better coding, but also so that I can get this project done faster!

def searchText(searchword):
    counts = []
    corpus_root = 'some_dir'
    wordlists = PlaintextCorpusReader(corpus_root, '.*')
    for id in wordlists.fileids():
        date = id[4:12]
        month = date[-4:-2]
        day = date[-2:]
        year = date[:4]
        raw = wordlists.raw(id)
        tokens = nltk.word_tokenize(raw)
        text = nltk.Text(tokens)
        count = text.count(searchword)
        counts.append((month, day, year, count))

    return counts

Answer 1

Run a profiler such as in the module profile and see what that says.

Answer 2

If you just want a frequency of word counts, then you don't need to create nltk.Text objects, or even use nltk.PlainTextReader. Instead, just go straight to nltk.FreqDist.

files = list_of_files
fd = nltk.FreqDist()
for file in files:
    with open(file) as f:
        for sent in nltk.sent_tokenize(f.lower()):
            for word in nltk.word_tokenize(sent):
                fd.inc(word)

Or, if you don't want to do any analysis - just use a dict.

files = list_of_files
fd = {}
for file in files:
    with open(file) as f:
        for sent in nltk.sent_tokenize(f.lower()):
            for word in nltk.word_tokenize(sent):
                try:
                    fd[word] = fd[word]+1
                except KeyError:
                    fd[word] = 1

These could be made much more efficient with generator expressions, but I'm used for loops for readability.